题目描述
给定一个数组A[0,1,...,n-1],请构建一个数组B[0,1,...,n-1],其中B中的元素B[i]=A[0]*A[1]*...*A[i-1]*A[i+1]*...*A[n-1]。不能使用除法。
class Solution {
public:
vector<int> multiply(const vector<int>& A) {
int size = A.size();
vector<int> B(size);
int temp = 1;
for(int i = 0; i < size; i++)
{
B[i] = temp;
temp = temp * A[i];
}
temp = 1;
for(int i = size - 1; i >= 0; i--)
{
B[i] = B[i] * temp;
temp = temp * A[i];
}
return B;
}
};