C++里枚举在循环里的问题

最新推荐文章于 2025-06-28 22:34:25 发布

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最新推荐文章于 2025-06-28 22:34:25 发布

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本文链接：https://blog.youkuaiyun.com/m0_37756557/article/details/78722324

在进行C++编程时，遇到枚举类型在循环中的使用出现异常。本文探讨了枚举在循环中的常见问题，包括枚举的定义、枚举与循环的交互以及可能导致的问题和解决方案。

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在测试枚举功能时遇到以下问题。

#include <iostream>
using namespace std;
enum gameresult
{
win,lose,tie,cancel
};

int main()
{
gameresult result;
for(gameresult count = win;count <= cancel; count++)
{
  result = gameresult(count);
  if(result == win)
  cout<<"the game was win!"<<endl;
  if(result == lose)
  cout<<"the game was lose."<<endl;
  if(result == tie)
  cout<<"the game was played"<<endl;
  if(result == cancel)
  cout<<"the game was cancelled!"<<endl;
}
getchar();
return 0;
}

调试结果为：error C2676: 二进制“++”:“gameresult”不定义该运算符或到预定义运算符可接收的类型的转换

分析原因为：gameresult是指针变量，只能赋值不能运算。后面改成了int定义count就好了，然后把count作为数组下坐标一样使用，调试就成功了。

下面是正确代码：

#include <iostream>
using namespace std;
enum gameresult
{
win,lose,tie,cancel
};

int main()
{
gameresult result;
for(int count = win;count <= cancel; count++)
{
  result = gameresult(count);
  if(result == win)
  cout<<"the game was win!"<<endl;
  if(result == lose)
  cout<<"the game was lose."<<endl;
  if(result == tie)
  cout<<"the game was played"<<endl;
  if(result == cancel)
  cout<<"the game was cancelled!"<<endl;
}

return 0;
}