题解
水题。
#include<iostream>
#include<cstdio>
using namespace std;
int n, t, current, request;
int main() {
scanf("%d", &n);
for(int i = 0; i < n; ++i) {
scanf("%d", &request);
if(request > current) t += (request - current) * 6;
else if(request < current) t += (current - request) * 4;
current = request;
t += 5;
}
printf("%d", t);
return 0;
}