Day of Week题解

最新推荐文章于 2025-12-06 09:52:47 发布

原创最新推荐文章于 2025-12-06 09:52:47 发布 · 1k 阅读

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#c++

这篇博客展示了如何使用Python的datetime库和C++编程来将输入的日期转换成对应的星期。Python代码直接调用了datetime库的功能，而C++代码通过手动计算实现了相同功能，包括判断闰年和累加天数。

Day of Week

题目描述
- python题解
- C++题解

题目描述

你好！这是你第一次使用 **Markdown编辑器** 所展示的欢迎页。如果你想学习如何使用Markdown编辑器, 可以仔细阅读这篇文章，了解一下Markdown的基本语法知识。

python题解

直接调用python的datetime库，这也太好用了

import datetime
while True:
    try:
        month = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October','November', 'December']
        d, m, y = input().split()
        print((datetime.datetime(int(y), month.index(m) + 1, int(d)).strftime("%A")))
    except:
        break

C++题解

#include<iostream>
#include<string>
#include<vector>

using namespace std;


int monthDays[2][12] = {
    {31,28,31,30,31,30,31,31,30,31,30,31},        // not leap year
    {31,29,31,30,31,30,31,31,30,31,30,31}        // leap year
};


bool isLeapYear(int year) {
    if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
        return true;
    return false;
}


int main() {
    int day=0,year=0,mon=0;
    int n = 0,week_day=0;
    string month;
    vector<string>M({ "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" });
    vector<string> W({ "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday" });
    while (cin >> day >> month >> year)
    {
        for (int i = 0; i < M.size(); ++i)
            if (M[i] == month)
                mon = i;
        n = 0;
        //从0年开始算
        for (int i = 0; i < year; ++i)
            n += isLeapYear(i) ? 366 : 365;
        for (int i = 0; i < mon; ++i)
            n += monthDays[isLeapYear(year)][i];
        n += day;
        n = n + 5;
        week_day = n % 7;
        cout << W[week_day] << endl;
    }
    return 0;
}