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package com.lyh.redis.test;
import java.util.List;
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.TimeUnit;
import org.junit.Test;
import redis.clients.jedis.Jedis;
public class SingleRedisTest2 {
public Jedis init(){
//一个Jedis对象对应这个一个Redis的实例
Jedis jedis = new Jedis("192.168.29.160",6379);
return jedis;
}
public void destroy(Jedis j){
//在关闭时断开连接,测试发现在操作之前调用这个方法后Jedis实例依然可以使用
j.disconnect();
}
@Test
public void testList1(){
System.out.println("1S=========================================");
Jedis j = init();
j.lpush("Friut","apple","banana","orange","xxx");
System.out.println("llen(Friut):"+j.llen("Friut"));
List<String> r = j.lrange("Friut",0,-1);
for(String v :r){
System.out.println("1range:"+v);
}
System.out.println("1E=========================================");
System.out.println("2S=========================================");
//从左边弹出一个元素,从左边进从组边出类似于一个栈
String lpopValue = j.lpop("Friut");
System.out.println("lpopValue:"+lpopValue+" llen(Friut):"+j.llen("Friut"));
List<String> rx = j.lrange("Friut",0,-1);
for(String v :rx){
System.out.println("2range:"+v);
}
System.out.println("2E=========================================");
System.out.println("3S=========================================");
//从Friut的右边弹出来一个元素并放入到另一个链表中(这个链表可以是存在的也可以是不存在的)
j.rpoplpush("Friut","newList");
List<String> lrange = j.lrange("newList",0,-1);
for(String v : lrange){
System.out.println("lrange:"+v);
}
System.out.println("3E========================================="); //
System.out.println("4S=========================================");
//获取一个元素 这个元素依然在链表中
String lastElement = j.lindex("newList",j.llen("newList")-1);
System.out.println("lastElement:"+lastElement);
System.out.println("4E========================================="); //
System.out.println("5S=========================================");
j.lset("newList", j.llen("newList")-1,"lsetValue");
System.out.println("newList的最后一个值被设置为:"+j.rpop("newList"));
System.out.println("5E=========================================");
System.out.println("6S=========================================");
//从左到有删除 apple元素 2次
j.lrem("Friut",2,"apple");
List<String> r1 = j.lrange("Friut",0,-1);
for(String v :r1){
System.out.println("1range:"+v);
}
System.out.println("6E=========================================");
System.out.println("7S=========================================");
//移除第4个到倒数第二个之外的所有元素
j.ltrim("Friut",3,j.llen("Friut")-2);
List<String> r3 = j.lrange("Friut",0,-1);
for(String v :r3){
System.out.println("1range:"+v);
}
System.out.println("7E=========================================");
destroy(j);
}
@Test
public void testList2(){
Jedis j = init();
String keyName = "r2";
j.lpush(keyName,"A","B");
int count = 3;
CountDownLatch latch = new CountDownLatch(count);
//由于在前面的队列中放入了2个元素现在要循环取3次所以必然会阻塞住
//当手动使用命令往r2列表中添加元素后进程会结束
Bget b = new Bget(j,count,TimeUnit.SECONDS,keyName, latch);
new Thread(b).start();
try {
latch.await();
} catch (InterruptedException e) {
e.printStackTrace();
}finally{
destroy(j);
}
}
}
/**
* 模拟Blpop
* @author MECHREVO
*/
class Bget implements Runnable{
private Jedis j;
private int count;
private TimeUnit unit;
private String keyName;
private CountDownLatch latch;
public Bget(){}
public Bget(Jedis j,int count,TimeUnit unit,String keyName,CountDownLatch latch){
this.j = j;
this.count = count;
this.unit = unit;
this.keyName = keyName;
this.latch = latch;
}
@Override
public void run() {
for(int i=0;i<count;i++){
try{
unit.sleep(1);
//阻塞式获取如果keyName列表中没有元素则等待直到超时或者有新元素被添加
List<String> blpop = j.blpop(100,keyName);
if(null != blpop){
System.out.println(blpop.get(0)+"-----"+blpop.get(1));
latch.countDown();
}
}catch(InterruptedException e){
e.printStackTrace();
}
}
System.out.println("run over....");
}
}
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