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package com.lyzx.day01;
import java.util.ArrayList; import java.util.List; import java.util.concurrent.CountDownLatch; /** * 曾经的面试题:(淘宝?) * 实现一个容器,提供两个方法 add,size * 写两个线程,线程1添加10个元素到容器中,线程2实现监控元素的个数,当个数到5个时,线程2给出提示并结束 * */ public class T5{ public static void main(String[] args) { CountDownLatch latch = new CountDownLatch(1); Arr<Object> arr = new Arr<Object>(latch); new Thread(new R2(latch)).start(); new Thread(new R1(arr)).start(); } } class Arr<E>{ private CountDownLatch latch; private List<E> arr = new ArrayList<E>(); public Arr(CountDownLatch latch){ this.latch=latch; } public synchronized boolean add(E e){ boolean v = arr.add(e); try { Thread.sleep(300); } catch (InterruptedException e1) { e1.printStackTrace(); } if(5 == size()){ latch.countDown(); } System.out.println("======"+size()); return v; } public synchronized int size(){ return arr.size(); } } class R1 implements Runnable{ private Arr<Object> arr; public R1(Arr<Object> arr){ this.arr=arr; } @Override public void run(){ for(int i=0;i<10;i++){ arr.add(new Object()); } } } class R2 implements Runnable{ private CountDownLatch latch; public R2(CountDownLatch latch){ this.latch= latch; } @Override public void run(){ try { latch.await(); } catch (InterruptedException e) { e.printStackTrace(); } System.out.println("now 。。。。。over.."); } } |