又看了看,树状数组,明白了以前死背的的东西。关于离线算法有了初步的认识。另外,今天看了看spfa算法,这些的确都淡忘了。
BIT.pas_code:
var
n,m,q,i,j,k,x1,y1,x2,y2:longint;
c:array[1..1000,1..1000] of longint;
z:char;
procedure modify(i,j,k:longint);
var temp:longint;
begin
temp:=j;
while i<=n do begin
j:=temp;
while j<=m do begin
c[i,j]:=c[i,j]+k;
inc(j,j and -j);
end;
inc(i,i and -i);
end;
end;
function sum(i,j:longint):longint;
var temp,ans:longint;
begin
temp:=j; ans:=0;
while i>0 do begin
j:=temp;
while j>0 do begin
ans:=ans+c[i,j];
dec(j,j and -j);
end;
dec(i,i and -i);
end;
exit(ans);
end;
begin
assign(input,'BIT.in'); reset(input);
assign(output,'BIT.out'); rewrite(output);
readln(n,m,q);
for i:=1 to q do
begin
read(z);
case z of
'C':begin
readln(x1,y1,k);
modify(x1,y1,k);
end;
'Q':begin
readln(x1,y1,x2,y2);
writeln(sum(x2,y2)-sum(x1-1,y2)-sum(x2,y1-1)+sum(x1-1,y1-1));
end;
end;
end;
close(input); close(output);
end.
depressedJ.cpp_code:
#include<iostream>
using namespace std;
const int MXN=100010;
const int MXQ=400010;
struct opt{
int t,q,n,x,y;
}w[MXQ];
int n,m,o,c[MXN];
void optinsert(int t,int q,int n,int x,int y) {
w[o].t=t; w[o].q=q; w[o].n=n; w[o].x=x; w[o].y=y;
o++;
}
bool cmp(const opt &a,const opt &b) {
return (a.n<b.n || (a.n==b.n&&a.t<b.t));
}
bool cmp2(const opt &a,const opt &b) {
return (a.t<b.t);
}
void modify(int i,int k) {
while (i<=n) {
c[i]+=k;
i+=i&(-i);
}
}
int search(int i) {
int ans=0;
while (i>0) {
ans+=c[i];
i-=i&(-i);
}
return(ans);
}
int main()
{
int i,k,x,y,a[MXN];
char st[3];
freopen("depressedJ.in","r",stdin);
freopen("depressedJ.out","w",stdout);
scanf("%d%d",&n,&m);
for(i=1;i<=n;i++) {
scanf("%d",&a[i]);
optinsert(0,0,a[i],i,0);
}
gets(st);
for(i=1;i<=m;i++) {
if (getchar()=='C') {
scanf("%d%d",&x,&k);
optinsert(i,1,a[x],x,0);
optinsert(i,0,k,x,0);
a[x]=k;
}else {
scanf("%d%d%d",&x,&y,&k);
optinsert(i,2,k,x,y);
}
gets(st);
}
for(i=1;i<=n;i++) optinsert(m+1,1,a[i],i,0);
sort(w,w+o,cmp);
for(i=0;i<o;i++)
if (w[i].q==2) w[i].y=search(w[i].y)-search(w[i].x-1);
else if (w[i].q==0) modify(w[i].x,1); else modify(w[i].x,-1);
sort(w,w+o,cmp2);
for(i=0;i<o;i++)
if (w[i].q==2) printf("%d\n",w[i].y);
return 0;
}
FloatingMedian.cpp_code:
#include<iostream>
#define NEXT(a) (((a)*mul+add)%M)
using namespace std;
const int M=65536;
int c[M+1];
void modify(int i,int k) {
while (i<=M) {
c[i]+=k;
i+=i&-i;
}
}
int find(int k) {
int i,cnt=0,ans=0;
for(i=16;i>=0;i--) {
ans+=1<<i;
if (ans>M||cnt+c[ans]>=k) ans-=1<<i;
else cnt+=c[ans];
}
return ans+1;
}
int main()
{
freopen("FloatingMedian.in","r",stdin);
freopen("FloatingMedian.out","w",stdout);
int seed,mul,add,n,k,i;
cin>>seed>>mul>>add>>n>>k;
int mid=(k+1)/2;
unsigned long a=seed,b=seed;
long long ans=0;
for(i=1;i<=n;i++) {
modify(a+1,1);
a=NEXT(a);
if (i>=k) {
ans+=find(mid)-1;
modify(b+1,-1);
b=NEXT(b);
}
}
cout<<ans<<endl;
return 0;
}
turncard.cpp_code:
#include<iostream>
using namespace std;
const int MXN=100010;
int n,m;
bool c[MXN];
void modify(int i) {
if (!i) return;
while (i<=n) {
c[i]=!c[i];
i+=i&(-i);
}
}
bool sum(int i) {
bool ans=0;
while (i>0) {
ans^=c[i];
i-=i&(-i);
}
return ans;
}
int main()
{
int i,x,y;
char st[3];
freopen("turncard.in","r",stdin);
freopen("turncard.out","w",stdout);
scanf("%d%d",&n,&m);
gets(st);
for(i=1;i<=m;i++) {
if (getchar()=='T') {
scanf("%d%d",&x,&y);
modify(y);
modify(x-1);
}else{
scanf("%d",&x);
if (sum(n)^sum(x-1)) puts("no"); else puts("yes");
}
gets(st);
}
return 0;
}
spfa.pas_code:
var
a,b,e:array[1..1000] of longint;
vis:array[1..2000] of boolean;
q,d,f:array[1..2001] of longint;
n,m,i,s,t:longint;
procedure qsort(l,r:longint);
var i,j,x,y:longint;
begin
i:=l;
j:=r;
x:=a[(l+r) shr 1];
repeat
while a[i]<x do inc(i);
while a[j]>x do dec(j);
if not(i>j) then begin
y:=a[i]; a[i]:=a[j]; a[j]:=y;
y:=b[i]; b[i]:=b[j]; b[j]:=y;
y:=e[i]; e[i]:=e[j]; e[j]:=y;
inc(i);
dec(j);
end;
until i>j;
if i<r then qsort(i,r);
if l<j then qsort(l,j);
end;
procedure spfa(s:longint);
var i,k,l,t:longint;
begin
fillchar(vis,sizeof(vis),0);
for i:=1 to n do d[i]:=maxlongint;
d[s]:=0;
l:=0;
t:=1;
q[1]:=s;
vis[s]:=true;
repeat
l:=l mod 10000 +1;
k:=q[l];
for i:=f[k] to f[k+1]-1 do
if d[k]+e[i]<d[b[i]] then
begin
d[b[i]]:=d[k]+e[i];
if not vis[b[i]] then begin
t:=t mod 10000 +1;
q[t]:=b[i];
vis[b[i]]:=true;
end;
end;
vis[k]:=false;
until l=t;
end;
Begin
readln(n,m);
for i:=1 to m do
readln(a[i],b[i],e[i]);
qsort(1,m);
for i:=1 to m do
if f[a[i]]=0 then f[a[i]]:=i;
f[n+1]:=m+1;
for i:=n downto 1 do
if f[i]=0 then f[i]:=f[i+1];
readln(s,t);
spfa(s);
writeln(d[t]);
end.