I Can Guess the Data Structure!
There is a bag-like data structure, supporting two operations:
1 x
Throw an element x into the bag.
2
Take out an element from the bag.
Given a sequence of operations with return values, you're going to guess the data structure. It is a stack (Last-In, First-Out), a queue (First-In, First-Out), a priority-queue (Always take out larger elements first) or something else that you can hardly imagine!
Input
There are several test cases. Each test case begins with a line containing a single integer n (1<=n<=1000). Each of the next n lines is either a type-1 command, or an integer 2 followed by an integer x. That means after executing a type-2 command, we get an element xwithout error. The value of x is always a positive integer not larger than 100. The input is terminated by end-of-file (EOF). The size of input file does not exceed 1MB.
Output
For each test case, output one of the following:
stack
It's definitely a stack.
queue
It's definitely a queue.
priority queue
It's definitely a priority queue.
impossible
It can't be a stack, a queue or a priority queue.
not sure
It can be more than one of the three data structures mentioned above.
Sample Input
6 1 1 1 2 1 3 2 1 2 2 2 3 6 1 1 1 2 1 3 2 3 2 2 2 1 2 1 1 2 2 4 1 2 1 1 2 1 2 2 7 1 2 1 5 1 1 1 3 2 5 1 4 2 4
Output for the Sample Input
queue not sure impossible stack priority queue
<span style="font-size:18px;">#include<iostream>
#include<cstring>
#include<algorithm>
#include<queue>
#include<stack>
#include<cmath>
#include<functional>
using namespace std;
stack<int>sta;
queue<int>que;
priority_queue<int,vector<int>,less<int> >pqu1;
bool cun[4];
int main()
{
int n;
int a,b;
while(cin>>n)
{
memset(cun,true,sizeof(cun));
while(!sta.empty())sta.pop();
while(!que.empty())que.pop();
while(!pqu1.empty())pqu1.pop();
while(n--)
{
cin>>a>>b;
if(a==1)
{
if(cun[1])sta.push(b);
if(cun[2])que.push(b);
if(cun[3])pqu1.push(b);
}
else
{
if(cun[1]&&!sta.empty()&&b==sta.top())
sta.pop();
else cun[1]=false;
if(cun[2]&&!que.empty()&&b==que.front())
que.pop();
else cun[2]=false;
if(cun[3]&&!pqu1.empty()&&b==pqu1.top())
pqu1.pop();
else cun[3]=false;
}
}
int res=0;
for(int i=1; i<5; i++)
if(cun[i])res++;
if(res==0)cout<<"impossible"<<endl;
else if(res>=2)cout<<"not sure"<<endl;
else if(cun[1])cout<<"stack"<<endl;
else if(cun[2])cout<<"queue"<<endl;
else cout<<"priority queue"<<endl;
}
return 0;
}
</span>