Given a string, find the first non-repeating character in it and return it’s index. If it doesn’t exist, return -1.
Examples:
s = “leetcode”
return 0.
s = “loveleetcode”,
return 2.
Note: You may assume the string contain only lowercase letters.
class Solution {
public:
int firstUniqChar(string s) {
int len = s.length();
int count[256] = {0};
for(int i=0;i<len;++i)
{
count[s[i]]++;
}
for(int i=0;i<s.length();++i)
{
if(count[s[i]]==1)
return i;
}
return -1;
}
};