LeetCode:Nim Game

本文介绍了一种Nim游戏的胜负策略,通过分析游戏规则,给出了一种判断玩家是否能赢得游戏的方法。当堆中有4的倍数个石头时,无论玩家如何行动,都将无法获胜。

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You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.

Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.

For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.

Hint:

If there are 5 stones in the heap, could you figure out a way to remove the stones such that you will always be the winner?

class Solution {
public:
    bool canWinNim(int n) {
        if(n%4==0)
            return false;
        else
            return true;
    }
};
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