CODE 8: Valid Palindrome

本文介绍如何通过Java代码判断给定字符串是否为回文串,考虑仅使用字母数字字符并忽略大小写。

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Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.

	public boolean isPalindrome(String s) {
		// Start typing your Java solution below
		// DO NOT write main() function
		if (null == s) {
			return false;
		}
		if (s.length() <= 1) {
			return true;
		}
		int i = 0;
		int j = s.length() - 1;
		while (i < j) {
			char a = s.charAt(i);
			char b = s.charAt(j);
			if (a < '0' || (a > '9' && a < 'A') || (a > 'Z' && a < 'a')
					|| a > 'z') {
				i++;
				continue;
			}
			if (b < '0' || (b > '9' && b < 'A') || (b > 'Z' && b < 'a')
					|| b > 'z') {
				j--;
				continue;
			}
			if (a == b || ((a < b) && (a + 32 == b))
					|| ((a > b) && (a - 32 == b))) {
				i++;
				j--;
			} else {
				break;
			}
		}
		if (i < j) {
			return false;
		} else {
			return true;
		}
	}


 

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