#include<iostream>
#include<cmath>
using namespace std;
int main(){
int n=0;
int m=0;
int count=0;
int count3=0;
int s[1000];
int a=0,b=0,c=0,e=0;
float d=0;
cin>>n;
for(int i=0;i<n;i++)
{
cin>>s[i];
if(s[i]%5==0)
{
if(s[i]%2==0)
a+=s[i];
}
if(s[i]%5==1)
{
b+=pow(-1,count)*s[i];
count++;
}
if(s[i]%5==2)
c++;
if(s[i]%5==3)
{
count3++;
d+=s[i];
}
if(s[i]%5==4)
{
if(s[i]>e)
e=s[i];
}
}
if(a==0)
cout<<"N"<<" ";
else
cout<<a<<" ";
if(b==0&&count==0)
cout<<"N"<<" ";
else
cout<<b<<" ";
if(c==0)
cout<<"N"<<" ";
else
cout<<c<<" ";
if(d==0)
cout<<"N"<<" ";
else
printf("%.1f ",d/count3);
if(e==0)
cout<<"N";
else
cout<<e;
return 0;
#include<cmath>
using namespace std;
int main(){
int n=0;
int m=0;
int count=0;
int count3=0;
int s[1000];
int a=0,b=0,c=0,e=0;
float d=0;
cin>>n;
for(int i=0;i<n;i++)
{
cin>>s[i];
if(s[i]%5==0)
{
if(s[i]%2==0)
a+=s[i];
}
if(s[i]%5==1)
{
b+=pow(-1,count)*s[i];
count++;
}
if(s[i]%5==2)
c++;
if(s[i]%5==3)
{
count3++;
d+=s[i];
}
if(s[i]%5==4)
{
if(s[i]>e)
e=s[i];
}
}
if(a==0)
cout<<"N"<<" ";
else
cout<<a<<" ";
if(b==0&&count==0)
cout<<"N"<<" ";
else
cout<<b<<" ";
if(c==0)
cout<<"N"<<" ";
else
cout<<c<<" ";
if(d==0)
cout<<"N"<<" ";
else
printf("%.1f ",d/count3);
if(e==0)
cout<<"N";
else
cout<<e;
return 0;
}
ps:注意A2可能有数字,但是在加减过程中令最后的结果为0即可