1510. Mispelling

本文深入探讨了程序开发的核心技巧与实践经验,从基础知识到高级应用,涵盖了前端、后端、移动开发等多个领域的关键技术,旨在帮助开发者提升编程能力,解决实际问题。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

1510. Mispelling

Description

Misspelling is an art form that students seem to excel at. Write a program that removes the nth character from an input string.

Input

The first line of input contains a single integer N , (1≤N≤1000) which is the number of datasets that follow.

Each dataset consists of a single line of input containing M , a space, and a single word made up of uppercase letters only. M will be less than or equal to the length of the word. The length of the word is guaranteed to be less than or equal to 80.

Output

For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the misspelled word. The misspelled word is the input word with the indicated character deleted.

Sample Input

4 
4 MISSPELL 
1 PROGRAMMING 
7 CONTEST 
3 BALLOON

Sample Output

1 MISPELL 
2 ROGRAMMING 
3 CONTES 
4 BALOON

Problem Source

Greater New York 2007


// source code of submission 966200, Zhongshan University Online Judge System
#include <iostream>
#include <string>
#include <cstring>
using namespace std;

int main()
{
    int n,m,len;
    string str;
    cin >> n;
    for (int k = 0;k < n; k++)
    {
        cin >> m >> str;
        len = str.length();
        cout << k+1 << " ";
        for (int i = 0;i < m-1;i++)
            cout << str[i];
        for (int i = m;i <= len-1; i++)
            cout << str[i];
        cout << endl;
    }
    return 0;
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值