最近在写CCF题把会的答案贴出来,希望能方便大家
试题编号: | 201609-2 |
试题名称: | 火车购票 |
时间限制: | 1.0s |
内存限制: | 256.0MB |
问题描述: | 问题描述 请实现一个铁路购票系统的简单座位分配算法,来处理一节车厢的座位分配。 输入格式 输入的第一行包含一个整数n,表示购票指令的数量。 输出格式 输出n行,每行对应一条指令的处理结果。 样例输入 4 样例输出 1 2 样例说明 1) 购2张票,得到座位1、2。 评测用例规模与约定 对于所有评测用例,1 ≤ n ≤ 100,所有购票数量之和不超过100。 |
代码:
package ccf;
import java.util.Scanner;
public class 火车购票 {
public static void main(String[] args) {
new 火车购票().run();
}
public void run() {
boolean flag=false;
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int[] a=new int[n];
for (int i = 0; i < a.length; i++) {
a[i]=sc.nextInt();
}
int[][] b=new int[20][5];
for (int i = 0; i < 20; i++) {
for (int j = 0; j < 5; j++) {
b[i][j]=0;
}
}
for (int i = 0; i < a.length; i++) {
if(a[i]==1){
flag=false;
for (int j = 0; j < 20; j++) {
for (int j2 = 0; j2 < 5; j2++) {
if(b[j][j2]==0){
b[j][j2]=1;
System.out.println((5*j+j2+1));
flag=true;
break;
}
}
if(flag){
break;
}
}
}
if(a[i]==2){
flag=false;
for (int j = 0; j < 20; j++){
for (int j2 = 0; j2 < 4; j2++){
if(b[j][j2]==0&&b[j][j2+1]==0){
b[j][j2]=1;
b[j][j2+1]=1;
System.out.print((5*j+j2+1)+" "+(5*j+j2+2));
flag=true;
break;
}
}
if(flag){
System.out.println("");
break;
}
}
if(!flag){
int count=0;
for (int j = 0; j < 20; j++) {
for (int j2 = 0; j2 < 5; j2++) {
if(b[j][j2]==0){
b[j][j2]=1;
System.out.print((5*j+j2+1)+" ");
count++;
if(count==2){break;}
}
}
if(count==2){
System.out.println("");
break;
}
}
}}
if(a[i]==3){
flag=false;
for (int j = 0; j < 20; j++){
for (int j2 = 0; j2 < 3; j2++){
if(b[j][j2]==0&&b[j][j2+1]==0&&b[j][j2+2]==0){
b[j][j2]=1;
b[j][j2+1]=1;
b[j][j2+2]=1;
System.out.print((5*j+j2+1)+" "+(5*j+j2+2)+" "+(5*j+j2+3));
flag=true;
break;
}
}
if(flag){
System.out.println("");
break;
}
}
if(!flag){
int count=0;
for (int j = 0; j < 20; j++) {
for (int j2 = 0; j2 < 5; j2++) {
if(b[j][j2]==0){
b[j][j2]=1;
System.out.print((5*j+j2+1)+" ");
count++;
if(count==3){break;}
}
}
if(count==3){
System.out.println("");
break;
}
}
}
}
if(a[i]==4){
flag=false;
for (int j = 0; j < 20; j++){
for (int j2 = 0; j2 < 2; j2++){
if(b[j][j2]==0&&b[j][j2+1]==0&&b[j][j2+2]==0&&b[j][j2+3]==0){
b[j][j2]=1;
b[j][j2+1]=1;
b[j][j2+2]=1;
b[j][j2+3]=1;
System.out.print((5*j+j2+1)+" "+(5*j+j2+2)+" "+(5*j+j2+3)+" "+(5*j+j2+4));
flag=true;
break;
}
}
if(flag){
System.out.println("");
break;
}
}
if(!flag){
int count=0;
for (int j = 0; j < 20; j++) {
for (int j2 = 0; j2 < 5; j2++) {
if(b[j][j2]==0){
b[j][j2]=1;
System.out.print((5*j+j2+1)+" ");
count++;
if(count==4){break;}
}
}
if(count==4){
System.out.println("");
break;
}
}
}
}
if(a[i]==5){
flag=false;
for (int j = 0; j < 20; j++){
for (int j2 = 0; j2 < 1; j2++){
if(b[j][j2]==0&&b[j][j2+1]==0&&b[j][j2+2]==0&&b[j][j2+3]==0&&b[j][j2+4]==0){
b[j][j2]=1;
b[j][j2+1]=1;
b[j][j2+2]=1;
b[j][j2+3]=1;
b[j][j2+4]=1;
System.out.print((5*j+j2+1)+" "+(5*j+j2+2)+" "+(5*j+j2+3)+" "+(5*j+j2+4)+" "+(5*j+j2+5));
flag=true;
break;
}
}
if(flag){
System.out.println("");
break;
}
}
if(!flag){
int count=0;
for (int j = 0; j < 20; j++) {
for (int j2 = 0; j2 < 5; j2++) {
if(b[j][j2]==0){
b[j][j2]=1;
System.out.print((5*j+j2+1)+" ");
count++;
if(count==5){break;}
}
}
if(count==5){
System.out.println("");
break;
}
}
}
}
}
sc.close();
}}
阿里云服务器,拼团特惠价86一年,有兴趣的小伙伴可以了解一下:https://www.aliyun.com/1111/2019/group-buying-share?
ptCode=68E176AAA4B1148EC82F42C7F69B54F8647C88CF896EF535&userCode=cd601crm&share_source=copy_link