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next_permutation函数  标签： 杂谈 分类： 函数 这是一个求一个排序的下一个排列的函数，可以遍历全排列,要包含头文件 下面是以前的笔记    与之完全相反的函数还有prev_permutation     (1) int 类型的next_permutation   int main() {  int a[3]; a[0]=1;a[1]=2;a[2]=3;

Orders Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 9432   Accepted: 5756 Description The stores manager has sorted all kinds of goods in an alphabetical

Fermat’s Chirstmas Theorem 题目描述 In a letter dated December 25, 1640; the great mathematician Pierre de Fermat wrote to Marin Mersenne that he just proved that an odd prime p is expressible as p

Surprising Strings Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5889   Accepted: 3856 Description The D-pairs of a string of letters are the ordered pairs

Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 18478   Accepted: 7323 Description Hardwoods are the botanical group of trees that have bro

Sequence Time Limit: 6000MS   Memory Limit: 65536K Total Submissions: 7312   Accepted: 2415 Description Given m sequences, each contains n non-negative integer. Now we ma

Black Box Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 7301 Accepted: 2976 Description Our Black Box represents a primitive database. It can save an i

题目描述  在一个果园里，多多已经将所有的果子打了下来，而且按果子的不同种类分成了不同的堆。多多决定把所有的果子合成一堆。 每一次合并，多多可以把两堆果子合并到一起，消耗的体力等于两堆果子的重量之和。可以看出，所有的果子经过n-1次合并之后，就只剩下一堆了。多多在合并果子时总共消耗的体力等于每次合并所消耗体力之和。 因为还要花大力气把这些果子搬回家，所以多多在合并果子时要尽可能地节省体力

题目描述 Well, how do you feel about mobile phone? Your answer would probably be something like that "It's so convenient and benefits people a lot". However, If you ask Merlin this question on the New