lucky_ax的博客

1，合并两个数组，合并两个对象ES5const a = [1,2,3];const b = [1,5,6];const c = a.concat(b);//[1,2,3,1,5,6] const obj1 = { a:1,}const obj2 = { b:1,}const obj = Object.assign({}, obj1, obj2);//{a:1,b:1}缺点：数组没有去重ES6const a = [1,2,3];const b = [1,5,6];c

去除重复的json对象原数据格式let arr = [ {name: "12",color: "hei se"}, {name: "13",color: "bai se"}, {name: "12",color: "hei se"}, {name: "16",color: "hong se"}, {name: "12",color: "hei se"}, {name: "18",color: "lv se"},]需求 取出数据中重复的name,删除重复项实现代码let temp