N!
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 61718 Accepted Submission(s): 17632
Problem Description
Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!
Input
One N in one line, process to the end of file.
Output
For each N, output N! in one line.
Sample Input
1 2 3
Sample Output
1 2 6
Author
JGShining(极光炫影)
一开始 不会做 但最后 终于能理解大数阶乘的算法了!
#include<iostream>
using namespace std;
int main()
{
int ls[10001];
int N,i,j;
while(cin>>N)
{
int m=0;ls[0]=1;
for( i=1;i<=N;i++)
{
int temp=0;
for(j=0;j<=m;j++)
{
ls[j]=ls[j]*i+temp;
temp=ls[j]/10000;
ls[j]=ls[j]%10000;
}
if(temp)
{
ls[++m]=temp;
}
}
cout<<ls[m];
for(int k=m-1;k>=0;k--)
printf("%04d",ls[k]);
cout<<endl;
}
return 0;
}