java——编号1006:Sign In and Sign Out

该篇博客介绍了如何使用Java编程语言解决一个实际问题,即根据每日的签到签出记录,找出当天最早签到和最晚签出的人,他们分别负责开门和关门。代码实现涉及时间处理和逻辑判断。

java——编号1006:Sign In and Sign Out

题目

At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in’s and out’s, you are supposed to find the ones who have unlocked and locked the door on that day.

Input Specification:

Each input file contains one test case. Each case contains the records for one day. The case starts with a positive integer M, which is the total number of records, followed by M lines, each in the format:
ID_number Sign_in_time Sign_out_time
where times are given in the format HH:MM:SS, and ID_number is a string with no more than 15 characters.

Output Specification:

For each test case, output in one line the ID numbers of the persons who have unlocked and locked the door on that day. The two ID numbers must be separated by one space.
Note: It is guaranteed that the records are consistent. That is, the sign in time must be earlier than the sign out time for each person, and there are no two persons sign in or out at the same moment.

Sample Input:

3
CS301111 15:30:28 17:00:10
SC3021234 08:00:00 11:25:25
CS301133 21:45:00 21:58:40

Sample Output:

SC3021234 CS301133

java实现


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

    private static Integer calTime(Integer hour, Integer minute, Integer second){
        return hour * 60 * 60 + minute * 60 + second;
    }
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        String unlockPersonId = "";
        String lockPersonId = "";
        Integer minTime = 0;
        Integer maxTime = 0;
        int personNumber = Integer.parseInt(br.readLine());
        for (int i = 0; i < personNumber; i++) {
            String line = br.readLine();
            String[] arr = line.split(" ");
            String id = arr[0];
            String signInTimeStr = arr[1];
            String signOutTimeStr = arr[2];
            String[] signInArr = signInTimeStr.split(":");
            Integer signInTime = calTime(Integer.parseInt(signInArr[0]), Integer.parseInt(signInArr[1]), Integer.parseInt(signInArr[2]));
            String[] signOutArr = signOutTimeStr.split(":");
            Integer signOutTime = calTime(Integer.parseInt(signOutArr[0]), Integer.parseInt(signOutArr[1]), Integer.parseInt(signOutArr[2]));

            if(i == 0){
                unlockPersonId = id;
                lockPersonId = id;
                minTime = signInTime;
                maxTime = signOutTime;
                continue;
            }
            if(signInTime < minTime){
                minTime = signInTime;
                unlockPersonId = id;
            }
            if(signOutTime > maxTime){
                maxTime = signOutTime;
                lockPersonId = id;
            }
        }
        System.out.printf("%s %s", unlockPersonId, lockPersonId);
    }
}

评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
红包 添加红包
表情包 插入表情
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值