苍竹林

# include # include # include using namespace std;int n,m,next[10010],a[1000010],b[10010];void Getnext(){ int i=0,j=-1; next[0]=-1; while(i<m) { if(j==-1||b[i]==b[j])

给定一个翻译表，即第i个字母用哪个字母表示  再给一个串，里面前面为密文，后面为明文，密文一定是完整的，但明文不完整或可能没有  求这个完整的前面密文后面明文的串 # include # include # include using namespace std;int len;int next[100010];char a1[100010],a2[1000

//len-next[len]为最小循环节的长度# include # include # include using namespace std;int len;char a[100010];int next[100010];void Getnext(){ int i=0,j=-1; next[0]=-1; while(i<=len) {

# include # include # include using namespace std;char a1[1000010],a2[1000010];int next[1000010];int len1,len2,cot;void Getnext(){ int i=0,j=-1; next[0]=-1; while(i<=len1) {

//给定一个由字符组成的矩阵，求出它的面积最小的覆盖矩阵//可以求出每一行的最小覆盖子串的长度，只要对这些长度求最小公倍数，就可以获得最小覆盖矩阵的宽度。//同理，求出每一列的最小覆盖子串的长度，再求最小公倍数，就可以获得最小覆盖矩阵的高度了。# include # include # include using namespace std;char a[10010][100];i

# include # include # include using namespace std;int len;char a[1000010];int next[1000010];void Getnext(){ int i=0,j=-1; next[0]=-1; while(i<=len) { if(j==-1||a[j]==a[

# include # include # include using namespace std;int next[100];char pat[100];char a[100][100];int ma;int lenp;int n;void Getnext(){ int i=0,j=-1; next[0]=-1; while(i<=lenp)