文章关键词:电子数据取证、手机取证、计算机取证、云取证、电子物证
龙信杯计算机检材-分析
前置
发现电脑中有EFS加密文件,故使用仿真软件保持原有密码进行仿真
1.分析计算机检材,嫌疑人在将其侵公数据出售前在Pycharm中进行了AES加密,用于加密的key是多少?[标准格式:1A23456ABCD]
参考答案:65B2564BG89F16G9
解题思路:
使用仿真软件对计算机检材进行仿真,打开桌面Pycharm软件,发现encrypted.py脚本,定位key值。
2.分析计算机检材,身份证为"371963195112051505"这个人的手机号码是多少?[标准格式:13013524420]
参考答案:15075547510
解题思路:
2.1根据key"65B2564BG89F16G9"、iv"83E6CBEF547944CF"对身份证"371963195112051505"进行加密
在线加密地址:https://www.mklab.cn/utils/aes
2.2 在文件中搜索对应值,解密当行其他值
3.分析计算机检材,对解密后的身份证数据列进行单列去重操作,重复的身份证号码数量是多少?(身份证不甄别真假)[标准格式:100]
参考答案:0
解题思路:
3.1 对加密文件“encrypted_data.txt”进行解密,编写代码如下:
import os
import time
from Crypto.Cipher import AES
from Crypto.Util.Padding import unpad
from concurrent.futures import ProcessPoolExecutor, as_completed
from tqdm import tqdm
defaes_decrypt(encrypted_data, key, iv):
cipher =AES.new(key, AES.MODE_CBC, iv)
decrypted_data =cipher.decrypt(encrypted_data)
unpadded_data =unpad(decrypted_data, AES.block_size)
returnunpadded_data.decode("utf-8")
defprocess_chunk(lines, key, iv):
result =[]
for line inlines:
parts =line.strip().split(',')
index = parts[0]
decrypted_parts = [index]
for part inparts[1:]:
encrypted_part = bytes.fromhex(part)
decrypted_part =aes_decrypt(encrypted_part, key, iv)
decrypted_parts.append(decrypted_part)
result.append(",".join(decrypted_parts)+ "\n")
return result
defget_file_line_count(file_path):
withopen(file_path, 'r', encoding='utf-8') as f:
line_count = sum(1for _ inf)
return line_count
defprocess_data(input_file, output_file, key, iv, num_workers=32, chunk_size=10000):
total_lines =get_file_line_count(input_file)
num_workers =min(num_workers, os.cpu_count() * 2)
withProcessPoolExecutor(max_workers=num_workers) as executor, \
open(input_file, "r") as f_in, \
open(output_file, "w") as f_out:
futures = []
lines_processed = 0
pbar = tqdm(desc="解密进度", unit="行", total=total_lines)
try:
whileTrue:
lines =[f_in.readline() for _ inrange(chunk_size)]
lines =list(filter(None, lines))
if notlines:
break
future =executor.submit(process_chunk, lines, key, iv)
futures.append((future, len(lines)))
forfuture, num_lines in futures:
iffuture.done():
result =future.result()