[贪心]codeforces - 651A Joysticks

本文探讨了两个游戏手柄在只有一个充电器的情况下如何通过合理的充电安排来延长游戏时间的问题。文章提供了一段AC代码,该代码能够计算出手柄在特定初始电量下可以持续游玩的最大时间。

Problem Description
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at a1 percent and second one is charged at a2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if not connected to a charger) or charges by 1 percent (if connected to a charger).

Game continues while both joysticks have a positive charge. Hence, if at the beginning of minute some joystick is charged by 1 percent, it has to be connected to a charger, otherwise the game stops. If some joystick completely discharges (its charge turns to 0), the game also stops.

Determine the maximum number of minutes that game can last. It is prohibited to pause the game, i. e. at each moment both joysticks should be enabled. It is allowed for joystick to be charged by more than 100 percent.

Input
The first line of the input contains two positive integers a1 and a2 (1 ≤ a1, a2 ≤ 100), the initial charge level of first and second joystick respectively.

Output
Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged.

Example
Input
3 5
Output
6
Input
4 4
Output
5
Hint
In the first sample game lasts for 6 minute by using the following algorithm:

at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%;
continue the game without changing charger, by the end of the second minute the first joystick is at 5%, second is at 1%;
at the beginning of the third minute connect second joystick to the charger, after this minute the first joystick is at 3%, the second one is at 2%;
continue the game without changing charger, by the end of the fourth minute first joystick is at 1%, second one is at 3%;
at the beginning of the fifth minute connect first joystick to the charger, after this minute the first joystick is at 2%, the second one is at 1%;
at the beginning of the sixth minute connect second joystick to the charger, after this minute the first joystick is at 0%, the second one is at 2%.
After that the first joystick is completely discharged and the game is stopped.

题意:
两个游戏手柄要充电,只有一个充电器,每分钟会消耗2%的电不充电的情况下,会得到1%的电充电时,不能同时充电和消耗,然后给出初始电量,问能最长玩多久。

//已AC代码
#include<iostream>
using namespace std;
int main()
{
     int a,b;
     int time=0;
     int flag=0;
     cin>>a>>b;
     while(a>0&&b>0)
     {
         if(a==b&&a==1)
         {
             cout<<"0"<<endl;
             flag=1;
             break;
         }
         if(a>b)
        {
            swap(a,b);
        }
         a=a+1;
         b=b-2;
         time++;

     }
     if(flag==0)
     cout<<time<<endl;
}
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