Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:Given the below binary tree and
sum
= 22
,
5 / \ 4 8 / / \ 11 13 4 / \ \ 7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2
which
sum is 22.
class Solution {
public:
bool hasPathSum(TreeNode *root, int sum) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if(root==NULL)
return false;
if(!root->left && !root->right && root->val==sum)
return true;
return root->left && hasPathSum(root->left,sum-root->val)|| root->right && hasPathSum(root->right,sum-root->val);
}
};