设计函数，不使用辅助数组，实现两个 int 类型或 double 类型数组的数据快速交换。

​#include <iostream>

using namespace std;

void zhuanhuan(int arr1[], int arr2[], size_t size) 
{
	for (size_t i = 0; i < size; ++i) 
	{
		arr1[i] = arr1[i] ^ arr2[i];
		arr2[i] = arr1[i] ^ arr2[i];
		arr1[i] = arr1[i] ^ arr2[i];
	}
}

int main()
 {

	int arr1[] = { 1, 2, 3, 4 };
	int arr2[] = { 5, 6, 7, 8 };

	size_t size = sizeof(arr1) / sizeof(arr1[0]);

	cout << "交换前：\n";
	for (size_t i = 0; i < size; ++i) 
	{
		cout << arr1[i] << " ";
	}
	cout << "\n";
	for (size_t i = 0; i < size; ++i) 
	{
		cout << arr2[i] << " ";
	}
	cout << "\n";

	zhuanhuan(arr1, arr2, size);

	cout << "交换后：\n";
	for (size_t i = 0; i < size; ++i) 
	{
		cout << arr1[i] << " ";
	}
	cout << "\n";
	for (size_t i = 0; i < size; ++i) 
	{
		cout << arr2[i] << " ";
	}
	cout << "\n";

	return 0;
}