C8-1 复数加减乘除
(100/100 分数)
题目描述
输入描述
输出描述
样例输入
样例输出
注释
求两个复数的加减乘除。
要求使用c++ class编写程序。可以创建如下class
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
class Complex{
public:
Complex(double r = 0.0, double i = 0.0): real(r), imag(i) {};
Complex operator+ (const Complex &c2) const;
Complex operator- (const Complex &c2) const;
/*实现下面三个函数*/
Complex operator* (const Complex &c2) const;
Complex operator/ (const Complex &c2) const;
friend ostream & operator<< (ostream &out, const Complex &c);
private:
double real;
double imag;
};
Complex Complex::operator+ (const Complex &c2) const {
return Complex(real + c2.real, imag + c2.imag);
}
Complex Complex::operator- (const Complex &c2) const {
return Complex(real - c2.real, imag - c2.imag);
}
int main() {
double real, imag;
cin >> real >> imag;
Complex c1(real, imag);
cin >> real >> imag;
Complex c2(real, imag);
cout << c1 + c2;
cout << c1 - c2;
cout << c1 * c2;
cout << c1 / c2;
}
输入描述
第一行两个double类型数,表示第一个复数的实部虚部
第二行两个double类型数,表示第二个复数的实部虚部
输出描述
输出依次计算两个复数的加减乘除,一行一个结果
输出复数先输出实部,空格,然后是虚部,
样例输入
1 1 3 -1
样例输出
4 0 -2 2 4 2 0.2 0.4
注释
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
class Complex{
public:
Complex(double r = 0.0, double i = 0.0): real(r), imag(i) {};
Complex operator+ (const Complex &c2) const;
Complex operator- (const Complex &c2) const;
/*实现下面三个函数*/
Complex operator* (const Complex &c2) const;
Complex operator/ (const Complex &c2) const;
friend ostream & operator<< (ostream &out, const Complex &c);
private:
double real;
double imag;
};
Complex Complex::operator+ (const Complex &c2) const {
return Complex(real + c2.real, imag + c2.imag);
}
Complex Complex::operator- (const Complex &c2) const {
return Complex(real - c2.real, imag - c2.imag);
}
Complex Complex::operator* (const Complex &c2) const{
return Complex(real*c2.real-imag*c2.imag,real*c2.imag+c2.real*imag);
}
Complex Complex::operator/ (const Complex &c2) const{//(a+bi)/(c+di)=((ac+bd)/(c*c+d*d))+((bc-ad)/(c*c+d*d))i 真是为难本文科生了
double a,b;
a=(real*c2.real+imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
b=(imag*c2.real-real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
return Complex(a,b);
}
ostream & operator<< (ostream &out, const Complex &c){
out<<c.real<<" "<<c.imag<<endl;
return out;
}
int main() {
double real, imag;
cin >> real >> imag;
Complex c1(real, imag);
cin >> real >> imag;
Complex c2(real, imag);
cout << c1 + c2;
cout << c1 - c2;
cout << c1 * c2;
cout << c1 / c2;
return 0;
}