https://leetcode.com/problems/binary-tree-preorder-traversal/
Given a binary tree, return the preorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1 \ 2 / 3
return [1,2,3]
.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> ans = new ArrayList<Integer>();
if (root == null) {
return ans;
}
Stack<TreeNode> rs = new Stack<TreeNode>();
TreeNode p = root;
while(p != null) {
ans.add(p.val);
if(p.right != null) {
rs.push(p.right);
}
p = p.left;
if(p == null && !rs.isEmpty()) {
p = rs.pop();
}
}
return ans;
}
}