From : https://leetcode.com/problems/merge-two-sorted-lists/
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first
two lists.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
ListNode *p=new ListNode(0);
ListNode *head=p;
while(l1 && l2) {
if(l1->val<l2->val) p->next=l1,l1=l1->next;
else p->next=l2,l2=l2->next;
p=p->next;
}
if(l1) p->next=l1;
if(l2) p->next=l2;
return head->next;
}
};
本文介绍如何使用C++编程语言将两个已排序的链表合并为一个有序链表,通过创建虚拟头节点并迭代比较两个链表的元素进行合并。
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