小写转大写程序

关于我们通常在数中有0的处理最为困难,比如:10000001,100000000搞了一整天,还有些问题.贴上来,作为一天努力的记录.等再有时间继续.

ubuntu 12.04 32bit gcc 4.6.3

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
/*小数转换大写程序 1.0
 * ljhhh0123@yahoo.com.cn 2013.5.12
 * 输入的double值在小数点前13位和小数点后2位以内似乎是精确的.
 * 用浮点来处理精确的银行钱数是肯定不行的.
 * */
char *DaXie[]= {
    "零","壹","贰","叁","肆","伍","陆","柒","捌","玖"
};
char* Name[]= {
//小数点前16位.
	"仟","佰","拾","万","仟","佰","拾","亿",
	"仟","佰","拾","万","仟","佰","拾","圆",
	"","角","分"
};
//第1个1为小数和点,第2个为结束符'\0'.
char buf[16+1+2+1];
int main() {
    double d;static int t=0;int m;
    int num;
    scanf("%lf",&d);
    printf("双精double值能表示为: ");
    sprintf(buf,"%19.2lf",d);//按四位一段分段放入缓冲区,必须配合缓冲区大小.
    if(23<strlen(buf)||d>999999999999999.99 || d<=0.0) {
        printf("超出本程序表示范围,程序退出");
        return 0;
    }
    fputs(buf,stdout);
    fputs("\n",stdout);
    fputs("大写表示为:",stdout);
    
    for(num=0; buf[num]!='\0'; num+=4) {
        int i;
        char last;
        if(buf[num]=='.') break;
        if(buf[num]=='0' &&buf[num+1]=='0'&&buf[num+2]=='0'&&buf[num+3]=='0'){
			if(t==0){
				if(strcmp(Name[num+3],"兆")==0 || strcmp(Name[num+3],"亿")==0|| strcmp(Name[num+3],"圆")==0 ){
					fputs(Name[num+i],stdout);
					t=1;
					continue;
				}
			}
		if(buf[num+4]=='.') {fputs("圆",stdout);	break;}
			continue;
		}
		//大的整数,后面一大串0
		m=num;
		while(buf[m]!='.'){
			if(buf[m]!='0') break;
			m++;
			}
		if(buf[m]=='.'){
			fputs("圆",stdout);
			break;
			}
        //一次取四位,并判断0的位置,删掉多余的0.符合人们通常的念法.
        for(i=0; i<4; i++) {
            if(buf[num+i]==' ') continue;
            if(buf[num+i]=='0') {
                last='0';//记住前导的0
                if(i==3) {//尾部的0,如4000,不需输出0,但如在万位则输出万.
                    fputs(Name[num+i],stdout);
                    break;
                }
                continue;
            }
            if(i==3) {
				if(last=='0') {//将前导的0输出且只输入一个.
                fputs(DaXie[last-'0'],stdout);
            }
                fputs(DaXie[buf[num+i]-'0'],stdout);
                fputs(Name[num+i],stdout);
                break;
            }
            if(last=='0') {//将前导的0输出且只输入一个.
                fputs(DaXie[last-'0'],stdout);
            }
            last=buf[num+i];
            fputs(DaXie[buf[num+i]-'0'],stdout);
            fputs(Name[num+i],stdout);

        }
		
    }
//输出小数点后的两位.
    for(num++; buf[num]!='\0'; num++) {
        if(buf[num]=='0')continue;
        fputs(DaXie[buf[num]-'0'],stdout);
        fputs(Name[num],stdout);
    }
    fputs("整\n",stdout);
    return 0;
}