Oracle Job 不执行

关于Oracle Job 不执行

2008-11-11 19:48

我们用的生产环境Job是可以正常执行的,但是在测试环境是不可以执行的 在网上查了一下原因如下 SQL> show parameter job NAME                                 TYPE        VALUE ------------------------------------ ----------- ------------------------------ job_queue_processes                  integer     0 job_queue_processes 这个参数设置成了0,可以通过语句 ALTER SYSTEM SET JOB_QUEUE_PROCESSES = 10 来解决 另外,看了一下Eygle的文章也有帮助,下面是链接过来的文章 转自:http://www.eygle.com/archives/2004/11/job_can_not_execute_auto.html 昨天接到研发人员报告，数据库定时任务未正常执行，导致某些操作失败。 开始介入处理该事故. 系统环境: SunOS DB 5.8 Generic_108528-21 sun4u sparc SUNW,Ultra-4 Oracle9i Enterprise Edition Release 9.2.0.3.0 - Production 1.首先介入检查数据库任务   $ sqlplus "/ as sysdba" SQL*Plus: Release 9.2.0.3.0 - Production on Wed Nov 17 20:23:53 2004 Copyright (c) 1982, 2002, Oracle Corporation. All rights reserved. Connected to: Oracle9i Enterprise Edition Release 9.2.0.3.0 - Production With the Partitioning, OLAP and Oracle Data Mining options JServer Release 9.2.0.3.0 - Production SQL> select job,last_date,last_sec,next_date,next_sec,broken,failures from dba_jobs; JOB LAST_DATE LAST_SEC NEXT_DATE NEXT_SEC B FAILURES INTERVAL ---------- --------- ---------------- --------- ---------------- - ---------- ---------------------------- 31 16-NOV-04 01:00:02 17-NOV-04 01:00:00 N 0 trunc(sysdate+1)+1/24 27 16-NOV-04 00:00:04 17-NOV-04 00:00:00 N 0 TRUNC(SYSDATE) + 1 35 16-NOV-04 01:00:02 17-NOV-04 01:00:00 N 0 trunc(sysdate+1)+1/24 29 16-NOV-04 00:00:04 17-NOV-04 00:00:00 N 0 TRUNC(SYSDATE) + 1 30 01-NOV-04 06:00:01 01-DEC-04 06:00:00 N 0 trunc(add_months(sysdate,1),'MM')+6/24 65 16-NOV-04 04:00:03 17-NOV-04 04:00:00 N 0 trunc(sysdate+1)+4/24 46 16-NOV-04 02:14:27 17-NOV-04 02:14:27 N 0 sysdate+1 66 16-NOV-04 03:00:02 17-NOV-04 18:14:49 N 0 trunc(sysdate+1)+3/24 8 rows selected. 发现JOB任务是都没有正常执行，最早一个应该在17-NOV-04 01:00:00执行。但是没有执行。 2.建立测试JOB   create or replace PROCEDURE pining IS BEGIN NULL; END; / variable jobno number; variable instno number; begin select instance_number into :instno from v$instance; dbms_job.submit(:jobno, 'pining;', trunc(sysdate+1/288,'MI'), 'trunc(SYSDATE+1/288,''MI'')', TRUE, :instno); end; / 发现同样的，不执行。 但是通过dbms_job.run(<job>)执行没有任何问题。 3.进行恢复尝试 怀疑是CJQ0进程失效，首先设置JOB_QUEUE_PROCESSES为0，Oracle会杀掉CJQ0及相应job进程 SQL> ALTER SYSTEM SET JOB_QUEUE_PROCESSES = 0; 等2~3分钟，重新设置 SQL> ALTER SYSTEM SET JOB_QUEUE_PROCESSES = 5; 此时PMON会重起CJQ0进程 在警报日志中可以看到以下信息:   Thu Nov 18 11:59:50 2004 ALTER SYSTEM SET job_queue_processes=0 SCOPE=MEMORY; Thu Nov 18 12:01:30 2004 ALTER SYSTEM SET job_queue_processes=10 SCOPE=MEMORY; Thu Nov 18 12:01:30 2004 Restarting dead background process CJQ0 CJQ0 started with pid=8   但是Job仍然不执行，而且在再次修改的时候，CJQ0直接死掉了。   Thu Nov 18 13:52:05 2004 ALTER SYSTEM SET job_queue_processes=0 SCOPE=MEMORY; Thu Nov 18 14:09:30 2004 ALTER SYSTEM SET job_queue_processes=10 SCOPE=MEMORY; Thu Nov 18 14:10:27 2004 ALTER SYSTEM SET job_queue_processes=0 SCOPE=MEMORY; Thu Nov 18 14:10:42 2004 ALTER SYSTEM SET job_queue_processes=10 SCOPE=MEMORY; Thu Nov 18 14:31:07 2004 ALTER SYSTEM SET job_queue_processes=0 SCOPE=MEMORY; Thu Nov 18 14:40:14 2004 ALTER SYSTEM SET job_queue_processes=10 SCOPE=MEMORY; Thu Nov 18 14:40:28 2004 ALTER SYSTEM SET job_queue_processes=0 SCOPE=MEMORY; Thu Nov 18 14:40:33 2004 ALTER SYSTEM SET job_queue_processes=1 SCOPE=MEMORY; Thu Nov 18 14:40:40 2004 ALTER SYSTEM SET job_queue_processes=10 SCOPE=MEMORY; Thu Nov 18 15:00:42 2004 ALTER SYSTEM SET job_queue_processes=0 SCOPE=MEMORY; Thu Nov 18 15:01:36 2004 ALTER SYSTEM SET job_queue_processes=15 SCOPE=MEMORY; 4.尝试重起数据库 这个必须在晚上进行   PMON started with pid=2 DBW0 started with pid=3 LGWR started with pid=4 CKPT started with pid=5 SMON started with pid=6 RECO started with pid=7 CJQ0 started with pid=8 QMN0 started with pid=9 .... CJQ0正常启动，但是Job仍然不执行。 5.没办法了... 继续研究...居然发现Oralce有这样一个bug 1. Clear description of the problem encountered: slgcsf() / slgcs() on Solaris will stop incrementing after 497 days 2 hrs 28 mins (approx) machine uptime. 2. Pertinent configuration information No special configuration other than long machine uptime. . 3. Indication of the frequency and predictability of the problem 100% but only after 497 days. 4. Sequence of events leading to the problem If the gethrtime() OS call returns a value > 42949672950000000 nanoseconds then slgcs() stays at 0xffffffff. This can cause some problems in parts of the code which rely on slgcs() to keep moving. eg: In kkjssrh() does "now = slgcs(&se)" and compares that to a previous timestamp. After 497 days uptime slgcs() keeps returning 0xffffffff so "now - kkjlsrt" will always return 0. . 5. Technical impact on the customer. Include persistent after effects. In this case DBMS JOBS stopped running after 497 days uptime. Other symptoms could occur in various places in the code. 好么，原来是计时器溢出了，一检查我的主机: bash-2.03$ uptime 10:00pm up 500 day(s), 14:57, 1 user, load average: 1.31, 1.09, 1.08 bash-2.03$ date Fri Nov 19 22:00:14 CST 2004   刚好到事发时是497天多一点.ft. 6.安排重起主机系统.. 这个问题够郁闷的，NND，谁曾想Oracle这都成... Oracle最后声称: fix made it into 9.2.0.6 patchset 在Solaris上的9206尚未发布...晕. 好了，就当是个经历吧，如果有问题非常不可思议的话，那么大胆怀疑Oracle吧，是Bug，可能就是Bug。 重起以后问题解决，状态如下: $ sqlplus "/ as sysdba" SQL*Plus: Release 9.2.0.3.0 - Production on Fri Nov 26 09:21:21 2004 Copyright (c) 1982, 2002, Oracle Corporation. All rights reserved. Connected to: Oracle9i Enterprise Edition Release 9.2.0.3.0 - Production With the Partitioning, OLAP and Oracle Data Mining options JServer Release 9.2.0.3.0 - Production SQL> select job,last_date,last_sec,next_date,next_sec from user_jobs; JOB LAST_DATE LAST_SEC NEXT_DATE NEXT_SEC ---------- --------- ---------------- --------- ---------------- 70 26-NOV-04 09:21:04 26-NOV-04 09:26:00 SQL> / JOB LAST_DATE LAST_SEC NEXT_DATE NEXT_SEC ---------- --------- ---------------- --------- ---------------- 70 26-NOV-04 09:26:01 26-NOV-04 09:31:00 SQL> SQL> select * from v$timer; HSECS ---------- 3388153 SQL> select * from v$timer; HSECS ---------- 3388319 SQL>   7.FAQ 一些朋友在Pub上问的问题 Q:对于不同平台，是否存在同样的问题? A:对于不同平台，存在同样的问题 因为Oracle使用了标准C函数gethrtime 参考: http://www.eygle.com/unix/Man.Page.Of.gethrtime.htm 使用了该函数的代码都会存在问题. 在Metalink Note:3427424.8 文档中，Oracle定义的平台影响为:Generic (all / most platforms affected) Q.计数器溢出，看了看job 中基本都是1天左右执行一次，如果设置 3 天执行一次的 job , 是否出问题的uptime 应该是 497*3 之后呢 ？ A:不会 Oracle内部通过计时器来增进相对时间. 由于Oracle内部hrtime_t使用了32位计数 那么最大值也就是0xffffffff 0xffffffff = 4294967295 slgcs()是10亿分之一秒，溢出在42949672950000000这个点上. 注意，这里0xffffffff，达到这个值时，本来是无符号整型，现在变成了-1，那么这个值递增时，+1 = 0了。 时间就此停住了。 我写了一小段代码来验证这个内容，参考： [oracle@jumper oracle]$ cat unsign.c #include int main(void){ unsigned int num = 0xffffffff; printf("num is %d bits long/n", sizeof(num) * 8); printf("num = 0x%x/n", num); printf("num + 1 = 0x%x/n", num + 1); return 0; } [oracle@jumper oracle]$ gcc -o unsign.sh unsign.c [oracle@jumper oracle]$ ./unsign.sh num is 32 bits long num = 0xffffffff num + 1 = 0x0 [oracle@jumper oracle]$   Q:内部时钟之一应该就是这个吧： v$timer 精确到1/100 秒的数据 没错! 注意前面说的: 4. Sequence of events leading to the problem If the gethrtime() OS call returns a value > 42949672950000000 nanoseconds then slgcs() stays at 0xffffffff. This can cause some problems in parts of the code which rely on slgcs() to keep moving. 也就是说如果gethrtime() 操作系统调用返回值大于42949672950000000（单位10亿分之一秒） 也就是说Oracle将得到一个cs值为4294967295的时间值 而4294967295值就是0xffffffff 所以当时v$timer的计时也就是: SQL> select * from v$timer; HSECS ---------- 4294967295 SQL> / HSECS ---------- 4294967295 SQL> / HSECS ---------- 4294967295 SQL>