kaptcha中文验证码

最新推荐文章于 2023-05-10 03:20:54 发布

原创最新推荐文章于 2023-05-10 03:20:54 发布 · 654 阅读

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本文介绍了如何使用特定的技术手段，如文本生成算法、字符编码转换、多语言处理等，来实现高效且多样化的文本内容创造。通过结合不同技术模块，不仅能够生成具有特定风格的文字，还能确保内容的准确性和适应性，适用于多种应用场景。

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package cn.com.jsoft.jframe.utils;

import java.io.UnsupportedEncodingException;
import java.util.Random;

import com.google.code.kaptcha.text.TextProducer;
import com.google.code.kaptcha.util.Configurable;

public class ChineseText extends Configurable implements TextProducer {

    public String getText() {
        int length = getConfig().getTextProducerCharLength();
        char[] chars = getConfig().getTextProducerCharString();
        String finalWord = "", firstWord = "";
        String[] array = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9",
                "a", "b", "c", "d", "e", "f" };

        Random rand = new Random();

        for (int i = 0; i < length; i++) {
            switch (rand.nextInt(3)) {
            case 1:
                firstWord = String.valueOf(chars[rand.nextInt(chars.length)]);
                break;
            case 2:
                int r1,
                r2,
                r3,
                r4;
                String strH,
                strL;// high&low
                r1 = rand.nextInt(3) + 11; // 前闭后开[11,14)
                if (r1 == 13) {
                    r2 = rand.nextInt(7);
                } else {
                    r2 = rand.nextInt(16);
                }

                r3 = rand.nextInt(6) + 10;
                if (r3 == 10) {
                    r4 = rand.nextInt(15) + 1;
                } else if (r3 == 15) {
                    r4 = rand.nextInt(15);
                } else {
                    r4 = rand.nextInt(16);
                }

                strH = array[r1] + array[r2];
                strL = array[r3] + array[r4];

                byte[] bytes = new byte[2];
                bytes[0] = (byte) (Integer.parseInt(strH, 16));
                bytes[1] = (byte) (Integer.parseInt(strL, 16));

                try {
                    firstWord = new String(bytes, "GB2312");
                } catch (UnsupportedEncodingException e) {
                    e.printStackTrace();
                }
                break;
            default:
                firstWord = String.valueOf(chars[rand.nextInt(chars.length)]);
                break;
            }
            finalWord += firstWord;
        }
        return finalWord;
    }
}