最小01矩阵,Dp求解;同求最大子矩阵和类似,采用行/列存储总长度/和;
#include <iostream>
#include<cstdio>
#include<cstring>
using namespace std;
#define MAXN 2010
int h[MAXN],r[MAXN],l[MAXN];
int map[MAXN][MAXN];
char str[2];
int n,m;
void all_0_matrix()
{
int i,j,max = 0;
memset(h,0,sizeof(h));
for(i = 0; i < n; i++)
{
for(j = 0 ; j < m; j++)
{
if(map[i][j] == 0)
h[j] ++;
else h[j] = 0;
}
for(j = 0; j < m; j ++)
{
l[j] = j;
while(l[j] > 0 && h[j] <= h[l[j] - 1])
l[j] = l[l[j] - 1];
}
for(j = m-1; j >= 0; j --)
{
r[j] = j;
while(r[j] < m-1 && h[j] <=h[r[j] + 1])
r[j] = r[r[j] + 1];
}
for(j = 0; j < m; j ++)
{
if((r[j] - l[j] + 1) * h[j] > max)
max = (r[j] - l[j] + 1) * h[j];
}
}
printf("%d\n",max);
}
int main()
{
int t, i , j, k, len, Case;
char ch;
scanf("%d",&Case );
while( Case-- )
{
scanf( "%d%d", &n, &m );
for(i = 0; i < n; i++)
{
for(j = 0; j < m; j++)
{
scanf("%d",&map[i][j]);
}
}
all_0_matrix();
}
}