int[][] array1 = new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
System.out.println("输出原始的数组");
for (int[] ints : array1) {
for (int anInt : ints) {
System.out.print(anInt + "\t");
}
System.out.println();
}
// 获取有效值的个数
int sum = 0;
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (array1[i][j] != 0) {
sum++;
}
}
}
int[][] array2 = new int[1 + sum][3];
array2[0][0] = 11;
array2[0][1] = 11;
array2[0][2] = sum;
// 遍历二维数组,将非零的值,存放稀疏数组中
int count = 0;
for (int i = 0; i < array1.length; i++) {
for (int j = 0; j < array1[i].length; j++) {
if (array1[i][j] != 0) {
count++;
array2[count][0] = i;
array2[count][1] = j;
array2[count][2] = array1[i][j];
}
}
}
// 输出稀疏数组
System.out.println("稀疏数组");
for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0] + "\t" +
array2[i][1] + "\t" +
array2[i][2]);
}
System.out.println("==============");
System.out.println("还原");
// 1. 读取稀疏数组
int[][] array3 = new int[array2[0][0]][array2[0][1]];
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];
}
for (int[] ints : array3) {
for (int anInt : ints) {
System.out.print(anInt + "\t");
}
System.out.println();
}
稀疏数组
最新推荐文章于 2024-02-22 13:44:18 发布