JAVA将String转换为json并用gson解析

最新推荐文章于 2025-06-21 15:04:58 发布

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最新推荐文章于 2025-06-21 15:04:58 发布

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分类专栏： java 文章标签： java json gson string

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本文展示了如何将前台传递的JSON数据转换为字符串，再使用Gson库将其解析为Map对象。首先，将JSON数据转化为JSONArray，然后获取其中的字符串，接着通过Gson的fromJson方法将字符串转换成Map，最后打印Map中的'deviceCode'值。

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前台传递过来的数据：

[{"aceneId":"","deviceCode":"27","deviceFirm":"春泉","deviceId":"1","deviceKind":"温控器","deviceName":"温控器001",

"deviceStation":"d8-b0-4c-b4-bc-a9","id":"110","isOn":"0","pattern":"制冷","permission":"1,00,99,0","registerAddress"

:"0081","registerNumber":"4","speed":"高档","temperature":"20","type":"0"},

{"aceneId":"","deviceCode":"16","deviceFirm":"春泉","deviceId":"2","deviceKind":"温控器","deviceName":"温控器002",

"deviceStation":"d8-b0-4c-b4-bc-a9","id":"111","isOn":"0","pattern":"制冷","permission":"1,00,99,0",

"registerAddress":"0081","registerNumber":"4","speed":"高档","temperature":"20","type":"0"}]

JSONArray jsonArray = JSONArray.fromObject(deviceList);
String jsonString =  jsonArray.getString(0);
Map deviceMap = new HashMap<>();
Gson gson = new Gson();
deviceMap = gson.fromJson(jsonString, deviceMap.getClass());
System.out.println(deviceMap.get("deviceCode").toString());