回文数判断

代码:

bool symm(int m)
{
	assert(m >= 0);
	int tmp = m;
	int n = 0;
	cout<<m;
	while(tmp)
	{
		n = n*10 + tmp%10;
		tmp /= 10;
	}
	cout<<"-->"<<n<<endl;
	return (m == n);
}

int main()
{
	int num = 0;
	while(1)
	{
		
		cout<<"Please input a natural number(or -1 to quit): ";
		cin>>num;
		if(num == -1)break;
		cout<<num<<(symm(num) ? "是" : "不是")<<"回文数"<<endl;
	}
	
	return 0;
}

结果: