:cry: 不要吐槽我为什么用sql语句来做urldecode。。。
但是当你遇到这种情况而且搜到的sql都只支持英文时,这篇文章就有用了
参考文章:
[url]http://psoug.org/snippet/url_decode_that_respects_utf8_characters_502.htm[/url]
[url]http://www.w3schools.com/tags/ref_urlencode.asp[/url]
原方法在替换'%0A'时转换失败,加多一句处理,其他特殊符号均可参照表格用同样方法提前替换。
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但是当你遇到这种情况而且搜到的sql都只支持英文时,这篇文章就有用了
参考文章:
[url]http://psoug.org/snippet/url_decode_that_respects_utf8_characters_502.htm[/url]
[url]http://www.w3schools.com/tags/ref_urlencode.asp[/url]
原方法在替换'%0A'时转换失败,加多一句处理,其他特殊符号均可参照表格用同样方法提前替换。
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DELIMITER $$
DROP FUNCTION IF EXISTS `url_decode` $$
CREATE DEFINER=`root`@`%` FUNCTION `url_decode`(original_text TEXT) RETURNS TEXT CHARSET utf8
BEGIN
DECLARE new_text TEXT DEFAULT NULL;
DECLARE pointer INT DEFAULT 1;
DECLARE end_pointer INT DEFAULT 1;
DECLARE encoded_text TEXT DEFAULT NULL;
DECLARE result_text TEXT DEFAULT NULL;
SET new_text = REPLACE(original_text,'+',' ');
SET new_text = REPLACE(new_text,'%0A','\r\n');
SET pointer = LOCATE("%", new_text);
while pointer <> 0 && pointer < (CHAR_LENGTH(new_text) - 2) DO
SET end_pointer = pointer + 3;
while MID(new_text, end_pointer, 1) = "%" DO
SET end_pointer = end_pointer+3;
END while;
SET encoded_text = MID(new_text, pointer, end_pointer - pointer);
SET result_text = CONVERT(UNHEX(REPLACE(encoded_text, "%", "")) USING utf8);
SET new_text = REPLACE(new_text, encoded_text, result_text);
SET pointer = LOCATE("%", new_text, pointer + CHAR_LENGTH(result_text));
END while;
return new_text;
END $$
DELIMITER ;