第五周:[Leetcode]455. Assign Cookies

解决一个经典的分配问题:如何通过合理分配不同大小的饼干给有不同需求的孩子们,使得尽可能多的孩子满意。通过排序和匹配策略来寻找最优解。

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Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example 1:
Input: [1,2,3], [1,1]
Output: 1
Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3.
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.
Example 2:
Input: [1,2], [1,2,3]
Output: 2
Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2.
You have 3 cookies and their sizes are big enough to gratify all of the children,
You need to output 2.


将两个数组排序,尽量以最小的代价满足孩子,依次下去,直至最大的cookie都不能满足小孩或者已经满足所有小孩。


class Solution {
public:
    int findContentChildren(vector<int>& g, vector<int>& s) {
    sort(g.begin(), g.end());
    sort(s.begin(), s.end());
    int i=0,j=0,ans = 0;
    while(i < g.size() && j < s.size()){
        if(g[i] > s[j])
            j++;
        else{
            i++;
            j++;
            ans++;
        }
    }
    return ans;
    }
};
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