Problem 1606 - Funny Sheep
Time Limit: 1000MS Memory Limit: 65536KB
Total Submit: 616 Accepted: 172 Special Judge: No
Total Submit: 616 Accepted: 172 Special Judge: No
Description
There are N+1 rows and M+1 columns fence with N*M grids on the grassland. Each grid has a sheep. In order to let the sheep together, we need to dismantle the fence. Every time you can remove a row or a column of fences. What’s the least number of times to reach the goal?
Input
There are multiple test cases.
The first line of each case contains two integers N and M. (1≤N,M≤1000)
The first line of each case contains two integers N and M. (1≤N,M≤1000)
Output
For each case, output the answer in a line.
Sample Input
1 2
2 2
2 2
Sample Output
1
2
2
AC-code:
#include<cstdio>
int main()
{
int n,m;
while(~scanf("%d%d",&m,&n))
{
if(m==n&&n==1)
{
printf("0\n");
}
else
printf("%d\n",n<m?n:m);
}
return 0;
}
本文探讨了一个有趣的算法问题——如何通过最少的步骤移除栅栏让所有羊聚集在一起。问题设定在一个由N+1行和M+1列组成的网格中,每个网格内有一只羊,目标是最小化移除栅栏的次数。
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