CodeForces 630A:Again Twenty Five!【水】

本文介绍了一个简单的编程面试题目,要求计算5的任意指定幂次方后得到的数字的最后两位数。示例代码使用C++实现,直接输出25作为答案。

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Again Twenty Five!
Time Limit:500MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u

Description

The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the number. Yes, of course, ncan be rather big, and one cannot find the power using a calculator, but we need people who are able to think, not just follow the instructions."

Could you pass the interview in the machine vision company in IT City?

Input

The only line of the input contains a single integer n (2 ≤ n ≤ 2·1018) — the power in which you need to raise number 5.

Output

Output the last two digits of 5n without spaces between them.

Sample Input

Input
2
Output
25
AC-code:
#include<cstdio>
int main()
{
	long long n;
	scanf("%lld",&n);
	printf("25\n");
	return 0;
 } 


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