import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class TestString
{
public static void main(String[] args)
{
String number = "333333222343423";
TestString test = new TestString();
if (test.isNumber1(number))
{
System.out.println(number);
}
if (test.isNumber2(number))
{
System.out.println(number);
}
}
/**
* 方法1
*/
private boolean isNumber1(String number)
{
Pattern pattern = Pattern.compile("[0-9]*");
Matcher matcher = pattern.matcher(number);
if (matcher.matches())
{
return true;
}
return false;
}
/**
* 方法2
*/
private boolean isNumber2(String number)
{
for (int i = 0; i < number.length(); i++)
{
if(Character.isDigit(number.charAt(i)))
{
return true;(注意:此判断为字符串中包含有数字,与isNumber1判断有异,请灵活运用)
}
}
return false;
}
}
本文来源于:http://zqc-0101.iteye.com/blog/1898312