mysql和admin中文问题

MYSQL错误:Illegal mix of collations (latin1_swedish_ci,COERCIBLE) and (gbk_chinese_ci,COERCIBLE) for operation '=' 一个解决办法

异常的意思是：字段字符集编码不同，不合法的连接。

用show full columns from tenant;命令查看tenant表各个字段的字符编码。

再用show full columns from employees;命令查看employees表各个字段的字符编码。

发现 tenant中的unitno字段和 employee中的unitno字段的字符编码类型不一致。一个是GBK的，一个是GB2312的。

然后用

ALTER TABLE `tenant` CHANGE `unitno` `unitno` VARCHAR( 32) CHARACTER SET gb2312 COLLATE gb2312_bin NOT NULL

命令修改tenant表中的nuitno字段的字符编码为gb2312类型。保证与整个数据库的字符编码gb2312一致。

 

或者使用alter table tenant convert to character set gb2312;命令，把整个表的字符编码设为gb2312。

mysql> SHOW VARIABLES LIKE 'character_set_%';
+--------------------------+----------------------------+
| Variable_name | Value |
+--------------------------+----------------------------+
| character_set_client | latin1 |
| character_set_connection | latin1 |
| character_set_database | latin1 |
| character_set_results | latin1 |
| character_set_server | latin1 |
| character_set_system | utf8 |
| character_sets_dir | /usr/share/mysql/charsets/ |
+--------------------------+----------------------------+
7 rows in set (0.00 sec)

mysql> SHOW VARIABLES LIKE 'collation_%';
+----------------------+-------------------+
| Variable_name | Value |
+----------------------+-------------------+
| collation_connection | latin1_swedish_ci |
| collation_database | latin1_swedish_ci |
| collation_server | latin1_swedish_ci |
+----------------------+-------------------+
3 rows in set (0.00 sec)

依次执行：

set character_set_client =gb2312;

set character_set_connection =gb2312;

set character_set_database =gb2312;

set character_set_results =gb2312;

set character_set_server =gb2312;

set character_set_system =gb2312; --此处utf-8也可以

然后执行：

SET collation_server = gb2312_chinese_ci

SET collation_database = gb2312_chinese_ci

SET collation_connection =gb2312_chinese_ci