UVA621 - Secret Research

最新推荐文章于 2017-09-06 14:55:20 发布

ACMega

最新推荐文章于 2017-09-06 14:55:20 发布

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本文解析了一个实验室中用于秘密研究的加密实验结果，包括正结果、负结果、实验失败及未完成四种状态，通过分析字符串模式来解密这些结果。

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没啥说的，题目没看懂，但是数据很一般，很好AC。

题目：

Secret Research

Secret Research

At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

`positive result',`negative result',`experiment failed' or`experiment not completed'

The encrypted result constitutes a string of digits S, which may take one of the following forms:



positive result 		 S = 1 or S = 4 or S = 78 

negative result 		 S = S35 

experiment failed 		 S = 9S4 

experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

You are to write a program which decrypts given sequences of digits.

Input

A integer n stating the number of encrypted results and thenconsecutive n lines, each containing a sequence of digits given as ASCII strings.

Output

For each analysed sequence of digits the following lines should be sent to output (in separate lines):


		 + 		  for a positive result
		 - 		  for a negative result
		 * 		  for a failed experiment
		 ? 		  for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

Sample Input

Sample Output

+
-
?
*

Miguel A. Revilla
2000-01-10

解答：

#include<stdio.h>
#include<string.h>
char str[100000];
int main()
{
	int t;
	scanf("%d",&t);
	getchar();
	int i;
	for(i=0;i<t;i++)
	{
		gets(str);
		if(strcmp(str,"1")==0||strcmp(str,"4")==0||strcmp(str,"78")==0)
			puts("+");
		else if(str[strlen(str)-2]=='3'&&str[strlen(str)-1]=='5')
			puts("-");
		else if(str[0]=='9'&&str[strlen(str)-1]=='4')
			puts("*");
		else if(str[0]=='1'&&str[1]=='9'&&str[2]=='0')
			puts("?");
	}
	return 0;
}