二分图
貌似还有并查集 by wxr 改编自hnoi
#include <cstdio>
#include <cstring>
#include <iostream>
#define D 5010
using namespace std;
typedef pair<int,int> pii;
int pr[D],ptot,n,q,u,v,cnt,tim,col[D],abandoned[D];
int hash[D];
pii sav[D];
struct edge {
int v,next;
}e[1000000];
int head[D];
int read () {
char c = getchar();
int re = 0;
while(c > '9' || c < '0')
c = getchar();
while(c <= '9' && c >= '0') {
re = re * 10 + c - '0';
c = getchar();
}
return re;
}
void adde (int u,int v) {
e[++cnt].v = v;
e[cnt].next = head[u];
head[u] = cnt;
e[++cnt].v = u;
e[cnt].next = head[v];
head[v] = cnt;
}
void reverse (int U,int ti) {
if(hash[U] == ti)
return;
col[U] ^= 1;
hash[U] = ti;
for(int i = head[U];i != -1;i = e[i].next) {
int V = e[i].v;
if(!abandoned[V])
reverse(V,ti);
}
}
int main () {
freopen("traf.in","r",stdin);
freopen("traf.out","w",stdout);
memset(head,-1,sizeof head);
n = read();
q = read();
for(int i = 1;i <= q;++i) {
u = read();
v = read();
if(u > v) {
int t = u;
u = v;
v = t;
}
sav[i].first = u;
sav[i].second = v;
}
for(int i = 1;i <= q;i++) {
for(int j = 1;j <= i - 1;++j) {
if(!abandoned[j]) {
if((((sav[j].first > sav[i].first) && (sav[j].first < sav[i].second)) && sav[j].second > sav[i].second)||(sav[j].first < sav[i].first && ((sav[j].second > sav[i].first) && sav[j].second < sav[i].second))) {
if(col[i] != col[j] ^ 1) {
reverse(i,++tim);
if(col[i] != col[j] ^ 1) {
abandoned[i] = 1;
pr[++ptot] = i;
break;
}
else adde(i,j);
}
else adde(i,j);
}
}
}
}
printf("%d\n",ptot);
for(int i = 1;i <= ptot;i++)
printf("%d\n",pr[i]);
return 0;
}

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