动态规划:
F[i][j]=F[i-1]+F[i][j-1]
class Solution {
public:
int uniquePaths(int m, int n) {
int res[100][100]={0};
res[0][0]=1;
for(int i=0;i<m;i++)
for(int j=0;j<n;j++)
{
if(j>=1)
res[i][j]+= res[i][j-1];
if(i>=1)
res[i][j]+=res[i-1][j];
}
return res[m-1][n-1];
}
};