DECLARE @date_from DATETIME; --开始日期
DECLARE @date_to DATETIME; --结束日期
SET @date_from = '2007-10-01';
SET @date_to = '2008-12-30';
select Convert(nvarchar(10),@date_from +(ABS(CAST(CAST( NewID() AS BINARY(8) )AS INT)) %CAST((@date_to - @date_from)AS INT)),23)
+ ' '+right('0'+cast( ABS(CAST(CAST( NewID() AS BINARY(8) )AS INT)) %24 as nvarchar(2)),2)
+':'+right('0'+cast(ABS(CAST(CAST( NewID() AS BINARY(8) )AS INT)) %60 as nvarchar(2)),2)
+':'+right('0'+cast(ABS(CAST(CAST( NewID() AS BINARY(8) )AS INT)) %60 as nvarchar(2)),2)
DECLARE @date_to DATETIME; --结束日期
SET @date_from = '2007-10-01';
SET @date_to = '2008-12-30';
select Convert(nvarchar(10),@date_from +(ABS(CAST(CAST( NewID() AS BINARY(8) )AS INT)) %CAST((@date_to - @date_from)AS INT)),23)
+ ' '+right('0'+cast( ABS(CAST(CAST( NewID() AS BINARY(8) )AS INT)) %24 as nvarchar(2)),2)
+':'+right('0'+cast(ABS(CAST(CAST( NewID() AS BINARY(8) )AS INT)) %60 as nvarchar(2)),2)
+':'+right('0'+cast(ABS(CAST(CAST( NewID() AS BINARY(8) )AS INT)) %60 as nvarchar(2)),2)
本文介绍了一种使用SQL语句生成特定格式时间戳的方法,包括开始日期、结束日期、毫秒、秒、分钟和小时的组合。
1487

被折叠的 条评论
为什么被折叠?



