SELECT A.* FROM test A,
(SELECT aid, MAX(day) max_day FROM test GROUP BY aid) B
WHERE A.aid = B.aid AND A.day = B.max_day
mysql 分组 排序 取时间最大的一条记录
最新推荐文章于 2025-06-16 16:10:05 发布
SELECT A.* FROM test A,
(SELECT aid, MAX(day) max_day FROM test GROUP BY aid) B
WHERE A.aid = B.aid AND A.day = B.max_day