统计元音字母——输入一个字符串，统计出其中元音字母的数量以及每个元音字母的数量

#include<iostream>
#include<string>
#include<ctype.h>
using namespace std;
int main() {
	string str;
	cin >> str;
	int sumCnt = 0;
	char l[5] = { 'a','e','i','o','u' };
	int count[5] = { 0 };
	for (int j = 0; str[j] != '\0'; j++) {
		if (str[j] == 'a'||str[j]=='A')
			count[0]++;
		if (str[j] == 'e' || str[j] == 'E')
			count[1]++;
		if (str[j] == 'i' || str[j] == 'I')
			count[2]++;
		if (str[j] == 'o' || str[j] == 'O')
			count[3]++;
		if (str[j] == 'u' || str[j] == 'U')
			count[4]++;
	}
	for (int i = 0; i < 5; i++) {
		if (count[i] != 0) {
            cout << l[i] << "  出现的次数为：  " << count[i] << endl;
			sumCnt += count[i];
		}
	}
	cout << "元音字母的总数为：" << sumCnt << endl;
	system("pause");
}