学习笔记

将输入的字符串以八个一组输出，不足的补零！

a = input().split(' ')
N = int(a[0] )
a = a[1:]
result = []
for m in a:
    if len(m) == 8:
        result.append(m)
    elif len(m) >8:
        n=m[:8]
        l=m[8:]
        result.append(n)
        a.append(l)
    else:
        k = 8-len(m)
        n = m+'0'*k
        result.append(n)
result.sort()
print(' '.join(result))

2 abc 123456789
12345678 90000000 abc00000

取出列表中不重复的元素！

array = input().split()
array.sort()
result = []
print(array)
for i in range(len(array)):
    if i == len(array) - 1:
        if array[i] != array[i - 1]:
            result.append(array[i])
    elif i == 0:
        if array[i] != array[i + 1]:
            result.append(array[i])
    elif (array[i] != array[i + 1]) and (array[i] != array[i - 1]):
            result.append(array[i])
print(result)

0 2 3 3 22 4 2 4 23 6 7
['0', '2', '2', '22', '23', '3', '3', '4', '4', '6', '7']
['0', '22', '23', '6', '7']