#include <stdio.h>
int main(void)
{
int n;
double sum=0.0000;
printf("please input n:\n");
scanf("%d",&n);
printf("Output:\n");
if(n<=0||n>=1000)
{
printf("Input error!\n");
}else{
printf("the ans is ");
while(n>0){
//printf("n=%d\n",n);
if(n%2==1){
sum+=(1.0000/n);
// printf("1234235\n");
}else{
// printf("999999\n");
sum-=(1.0000/n);
}
// printf("sum=%lf\n",sum);
--n;
}
printf("%.2lf\n",sum);
}
return 0;
}
求和问题
最新推荐文章于 2023-07-07 18:02:23 发布