mysql 根据昨天日期获取所有数据、本周数据、本月数据

最新推荐文章于 2024-11-08 16:02:03 发布

ldwtill

最新推荐文章于 2024-11-08 16:02:03 发布

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本文链接：https://blog.youkuaiyun.com/ldwtill/article/details/8720237

本文介绍了如何使用SQL语句来汇总不同时间段内的用户数据，并提供了具体的SQL代码示例，包括从日志表中统计每个用户的总记录数、同一月份及同一周内的活动次数，并展示了如何将这些统计数据更新到用户表中。

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从前到今天零点的所有数据:

SELECT count(*),uid from t_log where TO_DAYS(now()) > TO_DAYS(create_date) group by uid


与昨天在同一月的所有数据 :

SELECT count(*) ,uid from t_log WHERE TO_DAYS(now()) > TO_DAYS(create_date)

and DATE_FORMAT(create_date,'%Y-%m')=DATE_FORMAT(DATE_SUB(curdate(),INTERVAL 1 day),'%Y-%m') group by uid

与昨天在同一周的所有数据:

SELECT count(*) ,uid from t_log WHERE TO_DAYS(now()) > TO_DAYS(create_date) 
AND YEARWEEK(date_format(create_date,'%Y-%m-%d')) = YEARWEEK(DATE_SUB(curdate(),INTERVAL 1 day)) group by uid

根据上面获取的数据更新一个表：

UPDATE t_user t ,
(

SELECT totalnum,totalnummonth,totalnumweek,b.uid
from 

(SELECT count(*) totalnum ,uid from t_log where TO_DAYS(now()) > TO_DAYS(create_date) group by uid) b left join  
(SELECT count(*) totalnummonth ,uid from t_log WHERE TO_DAYS(now()) > TO_DAYS(create_date) 
and DATE_FORMAT(create_date,'%Y-%m')=DATE_FORMAT(DATE_SUB(curdate(),INTERVAL 1 day),'%Y-%m') group by uid) c  on b.uid=c.uid
  left join
(SELECT count(*) totalnumweek ,uid from t_log WHERE TO_DAYS(now()) > TO_DAYS(create_date) 
AND YEARWEEK(date_format(create_date,'%Y-%m-%d')) = YEARWEEK(DATE_SUB(curdate(),INTERVAL 1 day)) group by uid) d
on b.uid=d.uid
) a
set t.total_num = a.totalnum ,t.total_num_month = a.totalnummonth, t.total_num_week = a.totalnumweek
where t.uid = a.uid

参考文献：http://blog.163.com/lintingte@126/blog/static/48259543201121551331648/

http://www.blogjava.net/jjshcc/archive/2010/06/08/323053.html

http://www.111cn.net/database/mysql/43956.htm

http://zhidao.baidu.com/question/8707229.html