1-1/2+1/3-1/4+......-1/100

#include<stdio.h>
#include<stdlib.h>
double fac_1(int x)
{
double a = (1.0 / x);
return a;
}
double fac_2(int y)
{
double b = -(1.0 / y);
return b;
}
int main()
{ //计算1-1/2+1/3-1/4+…-1/100的值
int i = 0;
double sum1 = 0.0;
double sum2 = 0.0;
for (i = 1; i < 101; i += 2)
{
sum1 += fac_1(i);
}
for (i = 2; i < 101; i += 2)
{
sum2 += fac_2(i);

}
printf("%f\n", sum1+sum2);
system("pause");
return 0;

}