Steffensen

Steffensen迭代法matlab程序(《数值分析原理》) 《数值分析原理》课程中Steffensen迭代法的matlab程序。 阅读详情
#include <stdio.h>
#include<math.h>
double cal(double x,int option){
if(option==1)
return (3*x+1)/(x*x);
else if(option==2)
return (x*x*x-1)/3.0;
else if (option==3)
return pow(3*x+1,1.0/3.0);
else if(option==4)
return 1.0/(x*x-3);
else if(option==5)
return sqrt(3+1.0/x);
else 
return x-1.0/3.0*(x*x*x-3*x-1)/(x*x-1);
}
double judge(double y,double z,double x,double x0,double flag,int n,int N,int option)
{
printf("               迭代结果如下:\n");
printf("K         Xk          Yk          Zk \n");
while(n<=N)
{
y=cal(x0,option);
z=cal(y,option);
printf("%d    %lf      %lf   %lf\n",n,x0,y,z);
x=x0-(y-x0)*(y-x0)/(z-2*y+x0)*1.0;
if(fabs(x-x0)<flag)
{
return x;
}
++n;
x0=x;
}
return 0; 
}
int main()
{
double y=0,z=0,x=0,x0=0,flag=0;
int N=0,n=0,option=0;
for(;1>0;)
{
printf("请输入相应的计算格式:\n");
        printf(" ① x = (3x+1)/(x^2)② x = (x^3-1)/3 \n");
      printf("③ x = sqrt(3x+1) ④ x = 1/(x^2-3) \n");
   printf(" ⑤ x = pow((3+1/x),1/3) ⑥ x = x-(1/3)*(x^3-3x-1)/(x^2-1) \n");
   printf("\n请输入题号(0 退出): ");
scanf("%d",&option);
if(option)
{
printf("请输入初始值(x0),精度要求(flag),最大的迭代次数(N):\n");
scanf("%lf %lf %d",&x0,&flag,&N);
if(fabs(x=judge(y,z,x,x0,flag,n,N,option))>0)
printf("方程的近似解为:%lf\n",x);
else printf("不收敛!\n");
}
else return 0;
}
return 0;
}

matlab实现steffensen加速迭代、Newton法迭代 阅读详情

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应用Steffensen加速方法求解函数的MATLAB代码

Steffensen加速方法是一种改进的牛顿迭代法,可以用于求解不等式约束优化问题。下面是一个使用Steffensen加速方法求解函数的MATLAB代码:function [x,iter] = Steffensen(f,x0,tol,maxiter) % Steffensen's Method for solving nonlinear equations % Inputs % f: functi...

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数值分析(代码)-二分法、弦截法、Steffensen法的编程代码

二分法-习题2.1: 代码: Main.h: clc;clear;fromat long; secant(0,pi/4,10^(-8)); half .m: x=half(a,b,tol) c=(a+b)/2; k=1; m=1+round((log(b-a)-log(2*tol))/log(2)); while k<=m if f©==0 c=c; return; elseif f(a)*f©<0 b=(a+b)/2; else a=(a+b)/2; end c=(a+b)/2;k=k+1;

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